Lab 5 (C Programming) Solution
Feb 22, 2019programs written here are compiled and run in gcc (Ubuntu 7.3.0-27ubuntu1~18.04) 7.3.0
1)Write a program to read two numbers from user and find the sum of numbers between these two numbers(included) except the numbers divisible by 7.
Source Code:
#include <stdio.h>
int main()
{
int i,num1, num2, sum = 0;
printf("Enter the number to check:");
scanf(" %d %d", &num1, &num2);
for(i = num1; i <= num2; i++){
if(i%7 != 0){
sum += i;
}
}
printf("Sum = %d", sum);
return 0;
}
Output:
Enter the number to check:3 60 Sum = 1575
2)Write a program to check if the number entered by the user is prime or not.
Source Code:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int num,p_flag = 0,i;
printf("Enter the positive number to check prime:");
scanf("%d", &num);
if(num <= 0){
printf("Pleae Enter positive number.");
exit(0);
}
if(num == 1){
printf("It is NOT PRIME.");
exit(0);
}
for(i = 2; i <= num/2; i++){
if(num % i == 0){
p_flag = 1;
break;
}
}
if(p_flag == 0){
printf("It is PRIME.\n");
}else{
printf("It is NOT PRIME.\n");
}
return 0;
}
Output:
Enter the positive number to check prime:29 It is PRIME.
3)Write a program to display the Fibonacci series up to the number less than or equal to the number entered by the user.
Source Code:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int num, fnum = 0, snum = 1, temp = fnum + snum;
printf("Enter the number to print up to:");
scanf("%d", &num);
printf("\n %d,\t", fnum);
while(temp <= num){
printf("%d,\t", temp);
temp = fnum + snum;
fnum = snum;
snum = temp;
}
return 0;
}
Output:
Enter the number to print up to:1000 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, .
4)Write a program to find the sum of the following series. 1^2 + 3^2 + 5^2 + ………….. up to the odd number entered by the user
Source Code:
#include <stdio.h>
int main()
{
int num, sum = 0, i;
printf("Enter the positive odd number:");
scanf("%d", &num);
for(i = 1; i <= num; i += 2){
sum += i*i;
}
printf("SUM = %d\n", sum);
return 0;
}
Output:
Enter the positive odd number:25 SUM = 2925
5)Write a program to display the following patterns.(row number entered by the user)
Source Code(i):
#include <stdio.h>
int main()
{
int row_num, i, j;
printf("Enter odd row number:");
scanf("%d", &row_num);
for(i = 0; i < row_num; i++){
for(j = 0; j < row_num; j++){
if(i == j || i == row_num - j - 1){
printf("*");
}else{
printf(" ");
}
}
printf("\n");
}
return 0;
}
Output:
Enter odd row number:15
* *
* *
* *
* *
* *
* *
* *
*
* *
* *
* *
* *
* *
* *
* *
Source Code(ii):
#include <stdio.h>
int main()
{
int row_num, i, j;
printf("Enter row number:");
scanf("%d", &row_num);
for(i = 0; i < row_num; i++){
for(j = 0; j < row_num; j++){
if(i >= row_num - j -1){
printf("*");
}else{
printf(" ");
}
}
printf("\n");
}
return 0;
}
Output:
Enter row number:20
*
**
***
****
*****
******
*******
********
*********
**********
***********
************
*************
**************
***************
****************
*****************
******************
*******************
********************
Source Code(iii):
#include <stdio.h>
int main()
{
int row_num, i, j;
printf("Enter row number:");
scanf("%d", &row_num);
for(i = 0; i < row_num; i++){
for(j = 0; j < row_num; j++){
if(i >= j){
printf("%d\t", j+1);
}else{
printf(" \t");
}
}
printf("\n");
}
return 0;
}
Output:
Enter row number:10 1 1 2 1 2 3 1 2 3 4 1 2 3 4 5 1 2 3 4 5 6 1 2 3 4 5 6 7 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10
Source Code(iv) (Question 5-iv is changed):
#include <stdio.h>
int main()
{
int row_num, i, j, temp = 1;
printf("Enter row number:");
scanf("%d", &row_num);
for(i = 0; i < row_num; i++){
for(j = 0; j < row_num; j++){
if(j < row_num - i){
printf("%d\t", temp);
temp++;
}else{
printf(" \t");
}
}
printf("\n");
}
return 0;
}
Output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55